The first one is of order 5, so it has either 1, 3 or 5 real roots (unless any coefficent was complex). Proof complete :)
The other one, if it has a solution, it must be in [-1;1]. Because it only gives positive results the solution is further restricted to [0;1]. Because the cosine function is continuous and strictly decreasing on this interval, the difference of x and it's cosine will shrink up to some point within the interval where it gets to 0 (the solution) and then flips sign (the cosine gets less than the number), further decreasing until the end of the interval.
Answer:
6
Step-by-step explanation:
2(2y - 12) = 0
distribute the 2
2·2y - 2·12 = 0
4y - 24 = 0
add 24 to both sides
4y - 24 + 24 = 0 + 24
4y = 24
divide both sides by 4
(4y)/4 = 24/4
y = 6
Step 1: Add 1823 to both sides.
r−1823+1823=2312+1823=
r=4135
Answer is
