Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
Answer:
73/80
Step-by-step explanation:
multiples of 11 between 1 and 80 are 11,22,33,44,55,66,77
number of terms=7
P(multiple of 11)=7/80
P(not a multiple of 11)=1-7/80=73/80
8a^2 + 3a^2
11a^2
since both have a^2 you only have to add the coefficients
It is true that a parallelogram has symmetry with respect to the point of intersection of its diagonals.
The answer is D. 4x + 3y = -6
I first found the slope using the slope formula. Then I plugged in the values of the given coordinate and the slope I found into the point slope form equation, then I simplified. Then I manipulated the equation to get x and y on the right side, and the constant on the left side. Finally, I multiplied both sides by 3 to get rid of the fraction.