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3 years ago

What are the roots of the equation?

2 answers:

7 0

For the equation to = 0 , one of the components must = 0
x = 0
x = -13/9
x = -2/11

(Make each bracket = 0)
e.g. 9x+13=0
9x = -13
x = -13/9

quester [9]3 years ago

7 0

Answer:

x = 0

x = -13/9

x = -2/11

Step-by-step explanation:

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Part A.
The venn diagram is attached. In the venn diagram, circle A represent the number of responds that have an ASU parking deal. Circle B represent the number of respondents that ride their bike to campus and circle C represent the number of respondents that that ride the Light Rail.

Part B.
From the venn diagram, the number of respondents that ride the Light Rail and ride their bike to campus is given by 39 – 12 = 27

Part C.
From the venn diagram, the number of respondents that only have an ASU parking decal is given by 77 – 12 – 8 – 6 = 51

Part D.
The number of respondents that ride the Light Rail or have an ASU decal is given by the sum of the number of respondents that ride the Light Rail only and those that have an ASU parking decal and those that have both ASU parking decal and ride their bike to school.
This is given by 51 + 8 + 28 = 87.

Part E.
The venn diagram showing the area that represents people who have a parking decal or who ride their bike to campus but who do not ride the Light Rail sgaded is attached.

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3 years ago

In a Gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the Internet for shopping at l

svetoff [14.1K]

Answer: (0.25,0.33)

Step-by-step explanation:

A 99% confidence interval for population proportion is given by:-

$\hat{p}\pm 2.576\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = sample proportion, $n$ = sample size.

Given: $n=1025, \hat{p}=0.29$

A 99% confidence interval estimate of the proportion of adults who use the Internet for shopping:

$0.29\pm 2.576\sqrt{\dfrac{0.29(1-0.29)}{1025}}\\\\=0.29\pm 2.576\sqrt{0.00020087804878}\\\\=0.29\pm2.576(0.01417)\\\\=0.29\pm0.03650192\\\\=(0.29-0.03650192,\ 0.29+0.03650192)\\\\=(0.25349808,\ 0.32650192)$

$\approx(0.25,\ 0.33)$

Thus, a 99% confidence interval estimate of the proportion of adults who use the Internet for shopping = (0.25,0.33)

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3 years ago

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3 years ago

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