Question:
<em><u>A company sets up a food booth and a game booth at the county fair. The fee for the food booth is $100 plus $5 per day. The fee for the game both is $50 plus $7 per day. Write an expression for how much both will cost for the same number of days.</u></em>
Answer:
105 times 15= 1575
57 times 20= 1140
1140+1575= 2715
(2715)(d)= x
Answer:
78%
Step-by-step explanation:
% increase = Increase ÷ Original Number × 100
% increase= 35.8/46 *100= 77.82=78 %
Given 2.50x + 3.50y < 30.
Where x represent the number of hamburgers and y represent the number of cheeseburgers.
Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.
So, first step is to plug in y=4 in the given inequality. So,
2.50x+3.50(4)<30
2.50x+14 <30
2.50x<30- 14 Subtracting 14 from each sides.
2.50x< 16
Dividing each sides by 2.50.
x<6.4
Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,
thus x = 6 hamburgers
So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15
Hope this helps!!
Answer:
I would help but the thing is there is no options so sorry man
Step-by-step explanation: