We have that
<span>points A (-5, 6) and B (7, -1)
Part A)
find the distance
d=</span>√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193 units
Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5
the midpoint is (1,2.5)
Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12
the slope m=-7/12
Answer:
it would be 12
Step-by-step explanation:
9514 1404 393
Answer:
(a) no
(b) no
Step-by-step explanation:
The two questions are asking essentially the same thing. There is nothing that indicates DC ≅ DB or that AC ≅ AB. One (both) of these conditions is (are) required for ΔBAC to be isosceles, so that AD is both a perpendicular bisector of BC and a bisector of angle BAC.
There is not enough information to answer either question affirmatively.
Answer:
465371295673
Step-by-step explanation:
41354315431
Hello XD
3(x+2) = 3x+6
Distributive property
(3)(x)+(3)(2) = 3x+6
3x+ 6 = 3x+6
Now subtract 3x from both sides
3x+6-3x = 3x+6-3x
6=6
Subtract 6 from both sides
6-6 = 6-6
0=0
In this case the answer is : All real numbers are solution
