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Rina8888 [55]
3 years ago
12

Write n^4 • n^3 without exponents

Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

n*n*n*n*n*n*n

Step-by-step explanation:

n^4 * n^3 = n^7 = n*n*n*n*n*n*n

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If(2scos(pi/6) +2i sin(pi/2))^n =-64...n=??​
MrRa [10]

Answer:

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

Step-by-step explanation:

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

3 0
2 years ago
Jerry has a bag of 4 black marbles, 8 white marbles, 5 blue marbles, and 6 red marbles.
Luba_88 [7]

Answer:

11/23

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A pattern of letter arrangements begins with the 3 steps below. first continue the pattern for 3 more steps:
Anon25 [30]
1)
4. ABCDCBA
5. ABCDEDCBA
6. ABCDEFEDCBA

2) 1, 3, 5, 7, 9, 11

3) 19
6 0
3 years ago
Read 2 more answers
5x+15 - 2 = 2 - x+9
gavmur [86]

Answer:

-1/3

equation: 5x+13=-x+11

Step-by-step explanation:

1) combine like terms

5x+13=-x+11

5x+x=-13+11

6x=-2

x=-2/6

x=-1/3

7 0
3 years ago
Which ordered pair is a solution to the system of inequalities?
Butoxors [25]

For this case, what we must do is find a point that meets both inequalities.

  • <em>y> -2 </em>
  • <em>x + y <4 </em>

We have then:

For (0,4):

First inequation:

4> -2 (correct)

Second inequality:

0 + 4 <4 (incorrect)

For (1,4):

First inequation:

4> -2 (correct)

Second inequality:

1 + 4 <4 (incorrect)

For (-3,5):

First inequation:

5> -2 (correct)

Second inequality:

-3 + 5 <4 (correct)

Point (-3,5) is system solution

For (-2,-3):

First inequation:

-3> -2 (incorrect)

Answer:

Point (-3.5) is system solution

5 0
3 years ago
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