Answer:
Two, usually
Explanation:
A diploid plant has two copies (alleles) of every gene. If one copy of the gene is destroyed by a mutation, the plant will likely be okay with its other copy, and the trait will still be expressed.
However, some traits require both copies of the gene to be expressed. For example, if one gene is destroyed that means only half the amount of the gene product is produced. If that is not enough protein for the trait to be expressed, then the trait will be lost.
Prevent loss of Genetic Diversity and Inbreeding
The knowledge of parentage provides one with information about the origin and identity of the parents.
The variations and changes in the genes of the progeny of the parents can also be understood by the knowledge of the parentage.
Population of wild endangered species can benefit from the knowledge of parentage as this can help in prioritizing original gene material, avoid inbreeding incidents , important tool to manage cross between species hence aiding in the prevention of genetic diversity and loss of population.
In zoos, inbreeding is very common due to small populations which can lead to an increase in homozygous populations instead of heterozygous ones. Decrease in heterozygous populations implies decrease in genetic variability.
∴ Knowledge of parentage in zoos can help with that.
(to know more about Parentage : brainly.com/question/24506050)
Answer:
The correct answer is option - D. phosphorylation.
Explanation:
The CARD11 or caspase recruitment domain-containing protein 11 is a gene that provides instructions for gene expressing to make a protein in the function of lymphocytes in the immune system. Lymphocytes like B and T cells are activated with the help of cascade reactions in which these genes provide information.
The protein that activates is PKC which is a kinase enzyme that implicates that the process that activates CARD11 is phosphorylation.
Thus, the correct answer is option - d - phosphorylation.
Answer:
The organism is called a predator and the organism captured, a prey.
<h2>Law of independent assortment </h2>
Explanation:
- There are 8 distinct phenotypes, each one has a 12,5% of appearance: Since M=solid leaves D=normal height P= smooth skin.
- Recessive gene characters can only be taken in homozygous recessive mmddpp.
1. MmDdPp: M=solid leaves D=normal height P= smooth skin.
2. MmDdpp M=solid leaves D=normal height pp= peach skin.
3. MmddPp M=solid leaves dd=dwarf height P= smooth skin.
4. Mmddpp M=solid leaves dd=dwarf height pp= peach skin.
5. mmDdPp mm=mottled leaves D=normal height P= smooth skin.
6. mmDdpp mm=mottled leaves D=normal height pp= peach skin.
7. mmddPp mm=mottled leaves dd=dwarf height P= smooth skin.
8. mmddpp mm=mottled leaves dd=dwarf height pp= peach skin.
Hence,The answer is all eight possible phenotypes from the cross MmDdPp x mmddpp are equally likely, resulting in a phenotypic ratio of 1:1:1:1:1:1:1:1
