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hoa [83]
3 years ago
5

What restrictions are there on the range of the function H(w) below?

Mathematics
2 answers:
Bond [772]3 years ago
6 0

Answer: what he said ^

Step-by-step explanation:

Eddi Din [679]3 years ago
5 0
The function, named H(w) is defined by a graph that is a descendant line, that belongs only to the first quadrant. As w approaches to 0 by the right, the function approaches to + infinity. It never touches the vetical axis, decreases and approaches to 0 when w approaches to infinity. The graph never touches the horizontal - axis.

Then, the function is defined only for positive values of w and H(w) is always positive.

Then, the answer is H(w) > 0, this is the option C.  
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Ann's penny bank is 1/2 full. After she adds 120 pennies, it is 2/3 full. How many pennies can Ann's bank hold?
joja [24]

Her bank can hold 360 pennies.

Explanation:

Her bank was half full. Then, when she adds 120. It is 2/3. This would mean the 120 is 2/6 the amount the bank can hold. You would multiply that by 3 to get the total amount. That amount being 360.

Do you have any questions? Did I calculate something wrong?

Please tell me! I am happy to help people!

4 0
3 years ago
1) The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal
seropon [69]

Answer:

the height of the building is 86.6m

Step-by-step explanation:

In the right triangle, the height which we are looking for is the opposite side, since it is opposite to the angle 60°

Now we need to find the height of the building

tanθ = Opposite side/Adjacent side

tan 60° = Opp side/Adj side

1.7321 = Opp side/50

1.7321 x 50 = Opp side

Opp side = 50 x 1.7321

Opp side = 86.6 m

Therefore, the height of the building is 86.6m.

8 0
3 years ago
Find the slope of the line contain the given pair of points (-6,4) and (1,0)
EastWind [94]
(-6,4) \\
x_1=-6 \\
y_1=4 \\ \\
(1,0) \\
x_2=1 \\
y_2=0 \\ \\
\hbox{the slope}=\frac{y_2-y_1}{x_2-x_1}=\frac{0-4}{1-(-6)}=\frac{-4}{1+6}=-\frac{4}{7}

The slope is -4/7.
8 0
3 years ago
Read 2 more answers
What is the prime factorization for the number 20 using exponents
Alexxandr [17]
Prime factorization of 2·5·2=2^2·5
3 0
4 years ago
A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p
Kay [80]

Answer:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by V= 10 +t

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of \frac{A}{10+t}

So then we can reorder the differential equation like this:

\frac{dA}{dt} +\frac{A}{10+t} =8

We find the solution using the integration factor:

\mu = -\int \frac{1}{10+t} dt = -ln(10+t)

And then the solution would be given by:

A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})

And if we simplify this we got:

A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)

And after do the integral we got:

A= \frac{c}{10+t} +4 (10 +t)

And using the initial condition t=0 A= 20 we have this:

20 = \frac{c}{10} +40

c= -200

So then we have this function for the solution of A:

A= \frac{-200}{10+t} +4 (10 +t)

And now replacinf t= 40 we got:

A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196

8 0
3 years ago
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