Answer:
population of 1st city =660,000
Step-by-step explanation:
Let the population of second city be x
given that
population of the first city is equal to 32% of the population of the second city
Therefore
population of 1st city = 32% of the population of the second city
32% of x = (32/100)*x
total population of two cities = x + (32/100)*x = (100x+32x)/100 = 132x/100
Also, population of two cities = 660000
thus,
132x/100 = 660000
=> 132x = 660000*100 = 66000000
=> x = 66000000/132 = 2,062,500
Thus, population of 2nd city is 2,062,500
population of 1st city = (32/100)*x = 32/100 * 2,062,500 = 660,000
