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2 years ago

Simplify: x + (x-y) + y + (y-x )

Mathematics

1 answer:

AnnyKZ [126]2 years ago

3 0

Answer:

x + y

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

x + (x - y) + y + (y - x)

Step 2: Simplify

Combine like terms (x): x - y + y + y
Combine like terms (y): x + y

Read more on rotational symmetry;

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3 0

1 year ago

Katie wants to collect over 100100100 seashells. She already has 343434 seashells in her collection. Each day, she finds 121212

vekshin1

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The greater of two numbers is 5 more than the smaller. If the

xenn [34]

Answer:

First number = 4

Second number = 9

Step-by-step explanation:

If the first number = x, the second number = x + 5.

The calculation can be expressed as follows:

x + 2(x + 5) = 22

First, expand the bracket 2(x + 5):

x + 2x + 10 = 22

Combine like terms:

3x + 10 = 22

Subtract 10 from both sides:

3x = 12

Divide both sides by 3:

x = 4

First number = 4

Second number = 4 + 5 = 9

5 0

1 year ago

Donte simplified the expression below.

sergij07 [2.7K]

The answer is: [A]: He did not apply the distributive property correctly for 4(1 + 3i) .
_____________________________________________
Explanation:
______________________
Note the distributive property of multiplication:
_____________________________
a*(b+c) = ab + ac.
____________________________
As such: 4*(1 + 3i) = (4*1) + (4*3i) = 4 + 12i ;
_____________________________________
Instead, Donte somehow incorrectly calculated:
_____________________________________
4*(1 + 3i) = (4*1) + 3i = 4 + 31; (and did the rest of the problem correctly);

Note: - (8 - 5i) = -8 + 5i (done correctly;
___________________________________
So if Donte did not apply the distributive property correctly for 4*(1+3i)—and incorrect got 4 + 3i (as mentioned above); but did the rest of the problem correctly, he would have got:
_____________________________
4+ 3i - 8 + 5i = -4 + 8i (the incorrect answer as stated in our original problem.
__________________
This corresponds to: "Answer choice: [A]: He did not apply the distributive property correctly for 4(1 + 3i)."
___________________________

6 0

3 years ago

Read 2 more answers

The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

The probability of selecting a desktop is = $P(Desktop) = p_{Y} = \frac{5}{9}$

Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

$P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}$

(a)

Combination is used to determine the number of ways to select k objects from n distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0

2 years ago