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3 years ago

G(x)=4x²-3x+7Find g(3)From an algebra ii class in the section about functions.

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

6 0

Find the vertical asymptotes, if any, for the following function. Please show all of your work.

f(x) = -2x(x+2)/4x�-3x-7

To find vertical asymptotes, set denominator to 0, then solve for x

4x^2-3x-7=0

(x+1)(4x-7)=0

x+1=0

x=-1

4x-7=0

4x=7

x=7/4

Vertical Asymptotes:

x=-1

x=7/4

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What is the measure of ACB 105 150 65 impossible to determine

Assoli18 [71]

Answer:

impossible

Step-by-step explanation:

you need 3 different values including a side

4 0

3 years ago

The area of a rectangle is 4w - 10 square units.

podryga [215]

Area of rectangle = 2(2w - 5) is the factored form of given expression

Multiplying the length and width of a rectangle, we get the area of the rectangle

Solution:

Given that, area of rectangle is 4w - 10 square units

We have to factor the expression

From given,

Area of rectangle = 4w - 10

Take 2 as common factor

Area of rectangle = 2(2w - 5)

Thus the given expression is factored

The area of rectangle is given as:

$Area\ of\ rectangle = length \times width$

$Area\ of\ rectangle = 2 \times (2w - 5)$

Thus, multiplying the length and width of a rectangle, we get the area of the rectangle

When we multiply 2 with 2w - 5 we get the area of rectangle

From above we can say,

Length = 2 or 2w - 5

Width = 2w - 5 or 2

So when dimensions of rectangle are multiplied we get area of rectangle

3 0

3 years ago

3x-4 or = to 7 plz help

lisabon 2012 [21]

Answer:

3 + 4 = 7 which is true.

Step-by-step explanation:

Whenever you have an equation with a plain variable (that is, no exponent included), there is only one number that will work when substituted for x.

To solve it, you have to "undo" what is done to the variable. You also go in the reverse order of operations, so you do the addition/subtract first, then multiplication/division.

You also have to do the same to both sides, kind of like keeping a balance scale in balance.

In this case, we subtract 4 from both sides first:

3x + 4 -4 = 7 - 4

The + 4 - 4 cancel each other out, so you get:

3x = 3

3x means "3 times x" so you divide by 3 to undo it. I will use the / to indicate division:

3x / 3 = 3 /3

so 1x = 1.

Since 1x is "1 times x" it is the same as x by itself, so:

x=1

AND, if we substitute 1 back into the original equation (the asterisk stands for multiply):

3 * 1 + 4 = 7

3 * 1 is 3, so:

3 + 4 = 7 which is true.

1 is the only number that works.

Hope this helped.

3 0

3 years ago

Read 2 more answers

Pls help I’ll brainlest ASAP

svetlana [45]

Step-by-step explanation:

Given

-30 = - 0.4 k

30 = 0.4k

k = 30 / 0.4

k = 75

hope it helps :)

7 0

3 years ago

Read 2 more answers

Santa Claus is assigning elves to work an eight-hour shift making toy trucks. Apprentice earn five candy canes per hour but can

dimaraw [331]

Answer:

(a) 5 senior, 4 apprentice

(b) 368 per shift

Step-by-step explanation:

The problem can be described by two inequalities. On describes the limit on the number of elves in the shop; the other describes the limit on the total payroll. Let x and y represent the number of apprentice and senior elves, respectively. Then the inequalities for the first scenario are ...

x + y ≤ 9 . . . . . . . . . . . . total number of elves in the shop

5x +8y ≤ 480/8 . . . . . . candy canes per hour paid to elves

These two inequalities are graphed in the first attachment. They describe a solution space with vertices at ...

(x, y) = (0, 7.5), (4, 5), (9, 0)

(a) Santa wants to maximize the output of trucks, so wants to maximize the function t = 4x +6y.

At the vertices of the solution space, the values of this function are ...

t(0, 7.5) = 45

t(4, 5) = 46

t(9, 0) = 36

Output of trucks is maximized by a workforce of 4 apprentice elves and 5 senior elves.

(b) The above calculations show 46 trucks per hour can be made, so ...

46×8 = 368 . . . trucks in an 8-hour shift

(c) The new demands change the inequalities to ...

x + y ≤ 8 . . . . . . number of workers

7x +8y ≤ 60 . . . total wages (per hour)

The vertices of the feasible region for these condtions are ...

(x, y) = (0, 7.5), (4, 4), (8, 0)

From above, we know the truck output will be maximized at the vertex (x, y) = (0, 7.5). However, we know we cannot have 7.5 senior elves working in the shop. We can have 7 or 8 elves working.

If the workforce must remain constant, truck output is maximized by a workforce of 7 senior elves.

If the workforce can vary through the shift, truck output is maximized by adding one more senior elf in the shop for half a shift.

Santa should assign 7 senior elves for the entire shift, and 8 senior elves (one more) for half a shift.

_____

Comment on apprentice elf wages

At 5 candy canes for 4 trucks, apprentice elves produced trucks for a cost of 1.25 candy canes per truck. At 8 candy canes for 6 trucks, senior elves produced trucks for a cost of about 1.33 candy canes per truck. The reason for employing senior elves in the first scenario is that their productivity is 1.5 times that of apprentice elves while their cost per truck is about 1.07 times that of apprentice elves.

After the apprentice elves wages were increased, their cost per truck is 1.75 candy canes per truck, but their productivity hasn't changed. They have essentially priced themselves out of a job, because they are not competitive with senior elves.

5 0

3 years ago