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-BARSIC- [3]
3 years ago
7

The price of an item has been reduced by 15%. The original price was  $87.​

Mathematics
1 answer:
slavikrds [6]3 years ago
4 0

Answer:

The new cost is $73.95

The discount was $13. 05

Step-by-step explanation:

Turn the % into a decimal so it would be 0.15.

Then multiply it to the total, 87 x 0.15 = 13. 05

so the discount subtracted $13.05 off of the original price.

87 - 13. 05 = 73.95

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Angle sum theorem y=? Degrees
strojnjashka [21]

Answer:

2x + 70 = 110

x = 20

Step-by-step explanation:

180-110 = 70

70 + 20 + y = 180

y =90

4 0
3 years ago
Find the magnitude of vector v that has an initial point of (1, 3) and a terminal point of (7, 1)
solmaris [256]

Answer:

It's totally correct with no doubt

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3 years ago
So I have to compute the following but i don't know what they mean any help?
Gelneren [198K]

Answer:

Step-by-step explanation:

This is a Combination (as in permutation vs combination) question the symbol (n r) refers to "n choose r". This is sometimes written as nCr

i.e the question is asking you to find how many combinations each will yield when you chose r items from n item without repetition and order does not matter.

I will only do the first question for you and you can just follow the same steps to solve the rest of the questions.

Recall that

nCr=\frac{n!}{(r!)(n-r)!}

Consider question a) we are given (5 1) or ₅C₁

we can see that n = 5 and r = 1

If we substitute this into the formula:

₅C₁ = (5!) / [ (1!)(5- 1)!]

= (5!) / [ (5- 1)!]

= (5!) / (4!)

= (5·4·3·2·1) / (4·3·2·1)

= 5

hence ₅C₁ = 5

7 0
3 years ago
Read 2 more answers
Given that events A and B are independent with P(A)=0.3P(A)=0.3 and P(A\cap B)=0.27P(A∩B)=0.27, determine the value of P(B)P(B),
Stolb23 [73]

Answer:

0.9

Step-by-step explanation:

Since A and B are independent  hence;

P(A∩B) = P(A)P(B)

Given the following

P(A∩B) = 0.27

P(A) = 0.3

Required

P(B)

Substitute into the formula;

P(B) = P(A∩B)/P(A)

P(B) = 0.27/0.3

P(B) = 0.9

Hence the value of P(B) is 0.9

6 0
2 years ago
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