The two in 3,254,107 is in the hundred thousands place
The values of x at wich F(x) has local minimums are x = -2 and x = 4, and the local minimums are:
<h3>
What is a local maximum/minimum?</h3>
A local maximum is a point on the graph of the function, such that in a close vicinity it is the maximum value there. So, on an interval (a, b) a local maximum would be F(c) such that:
c ∈ (a, b)
F(c) ≥ F(x) for ∀ x ∈ [a, b]
A local minimum is kinda the same, but it must meet the condition:
c ∈ (a, b)
F(c) ≤ F(x) for ∀ x ∈ [a, b]
A) We can see two local minimums, we need to identify at which values of x do they happen.
The first local minimum happens at x = -2
The second local minimum happens at x = 4.
B) The local minimums are given by F(-2) and F(4), in this case, the local minimums are:
If you want to learn more about minimums/maximums, you can read:
brainly.com/question/2118500
Midsegment = 1/2(base1 + base2)
EF = 1/2(AB + CD)
EF = 1/2(20 + 12)
EF = 1/2(32)
EF = 16
Answer
EF = 16
Imagine there are 4 sits for fill for the debate team
we can fill the first sit in 35 different ways, second sit we only have 34 choices , third sit 33 and last sit 32 ways to possible fill it.
35·34·33·32=1,256,640 possible ways the team could be form
Answer:
The Area of Rectangular Garden is 1044 feet²
Step-by-step explanation:
According to question
The perimeter of the garden = 82 ft
Let the length be L ft
The width be W ft
Now as per question
L = 5 + ( 2× W )
∵ Perimeter of Rectangle = 2 × ( Length + Width )
Or , Perimeter of Rectangle = 2 × ( L+ W )
Or, 82 = 2 × ( L+ W )
Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]
Or, 82 = 2 × ( 5 +3W )
Or, 41 = 5 + 3W
Or, 41 - 5 = 3W
So, 3W= 36
∴ W = 
= 12 feet
I.e Width = 12 feet
And L = 5 + ( 2× W )
Or, Length = 5 + 24 = 29 feet
Now The Area of Rectangle = Length × width
So, The Area of Rectangle = 29 ft × 36 ft
The Area of Rectangle is 1044 feet²
Hence The Area of Rectangular Garden is 1044 feet² Answer
