How do you write an algebraic expression for 3 times the sum of x and y squared plus 5 times the difference of 2x and y
1 answer:
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8² (3x -2) + 5 = 56 I do the exponents first
64 (3x -2) + 5 = 56 I distribute the 64 over the 3x-2
192x - 128 + 5 = 56 I combined liked terms (-128+5)
192x -123 = 56 I add 123 to both side
192x - 123 +123= 56 + 123 Finally I divide both sides by 192
<u>192x</u> = <u>179
</u>192 192
x =
64 (3x -2) + 5 = 56 I distribute the 64 over the 3x-2
192x - 128 + 5 = 56 I combined liked terms (-128+5)
192x -123 = 56 I add 123 to both side
192x - 123 +123= 56 + 123 Finally I divide both sides by 192
<u>192x</u> = <u>179
</u>192 192
x =