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ololo11 [35]
3 years ago
14

Angles A and B are congruent. Find the value of x. Show all work to receive credit.

Mathematics
1 answer:
kolezko [41]3 years ago
8 0

Answer:

  x = 15

Step-by-step explanation:

Sides opposite congruent angles are congruent:

  x + 10 = 2x - 5

  15 = x . . . . . . . . . add 5-x

The value of x is 15.

_____

I suppose you could show the intermediate step:

  x +10 +(5 -x) = 2x -5 +(5 -x)

  15 = x . . . . . simplified

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7:6, unless it wants it simplified to decimals
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Sarah is saving to buy a new phone. She needs $150, and she has already saved $63. Write an equation to model this situation. Le
Lena [83]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
If Sarah is saving to buy a new phone. She needs $150, and she has already saved $63 then the equation should be $63 + x = $150
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3 years ago
I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit
makkiz [27]

Answer:

Possible answer: \displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6.

Step-by-step explanation:

Rewrite the bounds of c as fractions:

The simplest fraction for 1.5 is \displaystyle \frac{3}{2}. Write the upper bound 2 as a fraction with the same denominator:

\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}.

Hence the range for c would be:

\displaystyle \frac{3}{2} < c < \frac{4}{2}.

If the denominator of c is also 2, then the range for its numerator (call it p) would be 3 < p < 4. Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than 2.

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}.

\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}.

At this point, the difference between the numerators is now 2. That allows a number (7 in this case) to fit between the bounds. However, \displaystyle \frac{1}{c} = \frac{4}{7} can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}.

\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}.

\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}.

\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}.

\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}.

\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}.

It is important to note that some expressions for c can be simplified. For example, \displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5} because of the common factor 2.

Apparently \displaystyle c = \frac{16}{10} = \frac{8}{5} works. c = 1.6 while \displaystyle \frac{1}{c} = \frac{5}{8} = 0.625.

8 0
3 years ago
Read 2 more answers
why can you write a subtraction problem as an addition problem?How do you write a subtraction problem as an addition problem?
-Dominant- [34]

You can write a subtraction problem as a division problem by subtracting one of the addends from the sum, then your other addend would be the answer.

Example :

5 + 6 = 11

11 - 5 = 6


6 0
3 years ago
15 + 6f = 7f show steps please as soon as possible!
erica [24]

Answer:

f = 15

Step-by-step explanation:

15 + 6f = 7f

subtract 6f from each side

15= 1f

15=f

3 0
3 years ago
Read 2 more answers
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