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Ivenika [448]
3 years ago
12

The result of y times 2/7 is a wholenumber. What is a possible value of y?​

Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer:

The possible values of y will be the multiple of 7 , thus it would cancel out the denominator 7 in the fraction and it becomes a whole number

Pie3 years ago
6 0
Any value that is a multiple of 7
(2/7) * 7 = 2
(2/7) * 14 = 4
(2/7) * 21 = 6
And so on
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PLEASE HELP ASAP!!!!
DiKsa [7]

Answer:

1/3*9.7*Pi*7.6^2 ft^3 and then round to nearest tenth

Step-by-step explanation:

The trick is knowing that the volume of the cone is exactly 1/3 of the volume of the cylinder with the same radius & height. This relation can be derived using integrals.

7 0
3 years ago
-6+x=2x-5 what is the answer to this problem
Gnoma [55]

Answer:

x= -1

Step-by-step explanation

First move the variables to the left and change it's sign

(-6+x-2x=-5)

Then combine like terms

(-6-x=-5)

Then move the -6 to the right and combine it with the -5

(-x=-5+6)

(-x=1)

Lastly change the signs by dividing by 1

(x=-1)

8 0
4 years ago
Read 2 more answers
Shawn has two investments which both are compounded annually. Investment x earns 5% interest, and investment y earns 7% interest
Katena32 [7]

Answer:

0.18(0.05x + 0.07y) = t

explanation:

Trust me

6 0
3 years ago
Please help, I've been trying for an hour and I don't know how to set up this problem.
labwork [276]

Given ratio of the width of Francois's wife's vegetable garden to its length is 5:8.

Let l1,w1 be the length and width of Francois's wife's vegetable garden.

Then \frac{w1}{l1}  = \frac{5}{8}

Given ratio of the width of the herb garden to its length is 3:5.

Let l2,w2 be the length and width of herb garden.

That is \frac{w2}{l2} = \frac{3}{5}

Given that length of the herb garden is same as the width of the vegetable garden.

That is l2=w1 let this common value be x.

So, first ratio is \frac{x}{l1}=\frac{5}{8}

l1 = \frac{8x}{5}

Second ratio is \frac{w2}{x} = \frac{3}{5}

w2 = \frac{3x}{5}

perimeter of vegetable garden = 2(l1+w1) = 2(\frac{8x}{5} +x) = 2*\frac{13x}{5}  = \frac{26x}{5}

Perimeter of herb garden = 2(l2+w2) = 2(x+\frac{3x}{5} ) = 2*\frac{8x}{5} =\frac{16x}{5}

Given that francois has 252ft of fencing material.

That is perimeter of vegetable garden + perimeter of herb garden = 252

                                    \frac{26x}{5} +\frac{16x}{5}  = 252

                                               \frac{42x}{5} =252

                                                  x = \frac{252*5}{42} = 30 feet

So, l1 = \frac{8x}{5} = \frac{8*30}{5} = 48 feet

And w2 = \frac{3x}{5} = \frac{3*30}{5} = 18 feet

So dimensions of vegetable garden are 48ft, 30ft.

And dimensions of herb garden are 30ft,18ft.

4 0
4 years ago
The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e
Gnoma [55]

Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

We have the triangle PQR having co-ordinates (10,6), (6,2) and (4,-1).

It is required to translate ΔPQR so that the resulting image is completely inside the 2nd quadrant.

So, for that we will apply the following sequence of translations:

1. Translate 7 units up.

This will give us the figure in the 1st quadrant having co-ordinates (10,1), (6,9) and (4,6).

2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

5 0
4 years ago
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