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3 years ago

If the length of a rectangle is x + 4 and the width is 2x – 3, what is the area?

1 answer:

6 0

The area of a rectangle is the length times the width.

$(x+4) \times (2x-3)=2x^2-3x+8x-12=2x^2+5x-12$

The answer is C.

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Solve for w in P = 2w + 2l, if P = 38 and l = 12.

vova2212 [387]

W= 7

38=2w+2(12)
/
38=2w + 24
-24 -24

14=2w
divid by 2 divid by 2

7=w

4 0

3 years ago

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The following quadrilateral is a trapezoid. What is the measurement of the angle J?

GarryVolchara [31]

Answer:

Step-by-step explanation:

A trapezoid means that the lines are parallel, meaning that angle K + angle J = 180. So angle J = 180 = 115 = 65

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2 years ago

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If y varies directly with x and y = 5 when x = 4, find the value of y when x = -8

Ket [755]

Answer:

-10

Step-by-step explanation:

y : x

= 5 : 4

4z = -8

= -8 / 4 = -2 = z

y : x

= 5 * -2 : 4 * -2

= -10 : -8

7 0

2 years ago

PLEASE. It’s due in 30min.

olasank [31]

Answer:

BC, DB, CD

Step-by-step explanation:

The side opposite the largest angle must be the largest side and the side opposite the smallest angle must be the shortest. 96 degrees is opposite CD and 30 degrees is opposite BC.

6 0

2 years ago

A model rocket launched directly upward at a speed of 16 meters per second from a helght of 2 meters . The f(t) = - 4.9t ^ 2 + 1

Anton [14]

Answer:

f(t) = 15.06 m

Step-by-step explanation:

The relationship between the height of the rocket and the time after launch, t. In seconds is given by :

$f(t) = - 4.9t ^ 2 + 16t + 2$

We need to find the maximum height the rocket will reach the ground.

When it reaches the ground,

f(t) = 0

So,

Maximum height,

f'(t) = 0

$-9.8t+16=0\\\\t=\dfrac{16}{9.8}\\\\t=1.63\ s$

Put t = 1.63 in equation (1).

$f(1.63) = - 4.9\times (1.63 ^ 2) + 16(1.63) + 2\\\\=15.06\ m$

So, the maximum height of the rocket is 15.06 m.

4 0

2 years ago