The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 
⇒x=11t
Area of square=
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Answer:
The answer should be 8q-6 i think i tried
Step-by-step explanation:
36/2=18
18 would be your answer the radius is half of the diameter
The total weight of the liquid that filled the hemispheric tank to the nearest full pounds is 66775 pounds.
<h3>What is the volume of an hemisphere?</h3>
An hemisphere is half of a sphere. Therefore,
volume = 2 / 3 πr³
where,
Therefore,
r = 7 feet
volume = 2 / 3 × 3.14 × 7³
volume = 2 / 3 × 3.14 × 343
volume = 2154.04 / 3
volume = 718.013333333
volume = 718.013
Therefore,
density = mass / volume
93 = mass / 718.013
mass = 718.013 × 93
mass = 66775.24
mass ≈ 66775 pounds
learn more on hemisphere here: brainly.com/question/14527816
My teacher taught me a simple equation for these types of problems:
(percent of solution × amount of solution) + (percent of solution × amount of solution) = (percent of solution × total amount of solution)
in simple terms: %amount + %amount = %total amount
We know don't know how much gallons of 60% solution we need so it will be represented as x. We dont know the total amount either so it would have to be both solutions added together so 50 + x. Now lets solve:
(0.60)(x) + (0.24)(50) = (0.50)(50 + x) simplify/ distribute
0.6x + 12 = 25 +0.5x get all xs on one side and numbers on other
0.1x + 12 = 25
0.1x = 13 divide both sides by 0.1 to find x
x = 130
You need 130 gallons of 60% solution.