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atroni [7]
3 years ago
8

Find the reference angle for 497° A) 137° B)133° C) 47° D) 43°

Mathematics
2 answers:
vfiekz [6]3 years ago
6 0

Answer:

The reference angle is 43

Step-by-step explanation

Mila [183]3 years ago
4 0
Reference angle is 137
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All four sides of the baseball diamond are 90 ft long.
anastassius [24]

Answer:

d. 180 ft

Step-by-step explanation:

3 0
3 years ago
In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅
torisob [31]

Answer:

Step-by-step explanation:

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

iv) Diagonals must bisect each other.

v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.

6 0
2 years ago
At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive
schepotkina [342]
<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>
3 0
3 years ago
The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .
Novosadov [1.4K]

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A;  &

Let Claire be = C

A: C = 7 : 4

\dfrac{A}{C} =\dfrac{7}{4}

7C = 4A

C = \dfrac{4A}{7} --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

\dfrac{A}{C+68}= \dfrac{25}{41}

25(C + 68) = 41A

C + 68 = \dfrac{41}{25}A

C = \dfrac{41}{25}A - 68 --- (2)

Equating (1) and (2) together;

\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68

\dfrac{4 * A}{7}-\dfrac{41 *A}{25} =  - 68

\dfrac{100A - 287 A}{175} =- 68

\dfrac{-187A}{175} = -68

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; C = \dfrac{4A}{7}

C = \dfrac{4*64}{7}

C = 36.57

C ≅ 37 beads

4 0
3 years ago
I’ll make brainly if the answer is right
puteri [66]
The answer is A; 1/2. You add 1 1/2 and 1 1/2 together to get 3. Then you subtract 3 1/2 and 3 to get your answer 1/2. I hope that helps!
6 0
3 years ago
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