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3 years ago

Select all of the possible degrees of this polynomial function 2 3 4 5

Mathematics

2 answers:

rosijanka [135]3 years ago

7 0

Answer:

3 and 5

Step-by-step explanation:

correct on edge 2020

Dafna1 [17]3 years ago

6 0

Answer:

it there n image

Step-by-step explanation:

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14x to the power of -2 , for x=7

OverLord2011 [107]

Answer:

:5:5&&'4&4&4&:&;4"33*2**223$&4&4&55&

6 0

2 years ago

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Solve five ninths minus two sixths equals blank.

larisa [96]

Answer:

6/3 I think so try c and if it’s not I’m not sure

Step-by-step explanation:

6 0

3 years ago

The probabilty of getting an A in math is 0.65 and the probability of getting an a in science is 0.62 whats the probability of g

ruslelena [56]

Answer:

The probability of getting an a in both courses is 1.27

Step-by-step explanation:

Probability of getting A in Math, P(M) = 0.6 5

Probability of getting A in Science, P(S) = 0.62

Required probability of getting A in both courses, P(M and S)

= P(M) + P(S)

= 0.65 + 0.62

= 1.27

6 0

3 years ago

What are the square roots of 144/256

adelina 88 [10]

Answer:

Step-by-step explanation:

12*12=144

-12*-12=144

16*16=256

-16*-16=256

3 0

3 years ago

Read 2 more answers

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

3 years ago