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3 years ago

(2x² + 3x + 2)-( x² - 4x - 1)

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

7 0

Answer:69

Step-by-step explanation:

shtirl [24]3 years ago

3 0

Kdskksakskskskwkxjsnsjjakkwa

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RS bisects QRT, mangleQRS = (3x + 8), and mangleSRT = (5x − 4).

Leya [2.2K]

Bisect typically means half but since we aren't given angle at the start so we can just have to solve for x.

(3x + 8) = (5x - 4)

3x = 5x - 12

-2x = -12

x = 6

Best of Luck!

5 0

3 years ago

Can someone help me with this math problem

zepelin [54]

Answer:

$50.50 = 18 + 5n

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=x%20%2B%207%20%20%3C%20%20-%202" id="TexFormula1" title="x + 7 < - 2" alt="x + 7 < -

vladimir1956 [14]

First one because when you subtract 7 u keep the var. x alone and isolate it.

5 0

2 years ago

Math again yay!...Ew math

Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

$f(x)=x^2$

New function:

$g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2$

Transformations:

For a > 0

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}$

$\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\ & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}$

If the parent function is shifted ¹/₄ unit up:

$\implies g(x)=x^2+\dfrac{1}{4}$

If the parent function is shifted ¹/₄ unit down:

$\implies g(x)=x^2-\dfrac{1}{4}$

If the parent function is compressed vertically by a factor of ¹/₄:

$\implies g(x)=\dfrac{1}{4}x^2$

If the parent function is stretched horizontally by a factor of ¹/₂:

$\implies g(x)=\left(\dfrac{1}{2}x\right)^2$

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0

1 year ago

I need help on #10

Ede4ka [16]

D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)

Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1

6 0

3 years ago