Answer:
0.5054
Step-by-step explanation:
This is a question on conditional probability.
We solve using Baye's Theorem of conditional probability
From the question
The probability of having a particular disease = 0.08.
The probability of not having a particular disease = 1 - 0.08 = 0.92
The probability of testing positive for the disease is given that a person has the disease = 0.94
The probability of testing positive given that the person does not have the disease = 0.08
Given that a person tests positive for the disease, the probability that they actually have the disease is
= (0.08 × 0.94)/(0.08 × 0.94) + (0.08 × 0.92)
= 0.0752/0.0752 + 0.0736
=0.0752/ 0.1488
= 0.5053763441
≈ Approximately to 4 decimal places = 0.5054
Answer:
20. 300π m³
21. 457 1/3 π cm³
Step-by-step explanation:
20. r = 10 ÷ 2 = 5
V = 5² × 12 × π = 25 × 12π=300π m³
21. r = 14 ÷ 2 = 7
V = \frac{4}{3} \pi 7x^{3}
V = 457 1/3 π cm³
I can bring it down, and leave it to enough to simplify for you. The answer is 38.01315561.Any questions just ask! :)
45b + 27 = 9(5b + 3)
gcf = 9
The answer is 0.45
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Work Shown:
P(B|A) = P(B and A)/P(A)
0.2 = P(B and A)/0.9
0.2*0.9 = P(B and A)
0.18 = P(B and A)
P(B and A) = 0.18
P(A and B) = 0.18
P(A|B) = P(A and B)/P(B)
P(A|B) = 0.18/0.4
P(A|B) = 0.45
