The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
<u />
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be



= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
Answer:
x^2 -2x = 4x+1
2x^2 +12x = 0
9x^2 +6x -3=0
Step-by-step explanation:
A quadratic equation has the highest power of x being squared
x^2 -2x = 4x+1
2x^2 +12x = 0
9x^2 +6x -3=0
These are all quadratic equations
Answer:
131 points
Step-by-step explanation:
Apex. Sad nobody came in clutch for me
Answer:
All you do is just multiply them.
Step-by-step explanation:
5a^2 b^4(3ab^3)^2=
45(a^(4))(b^(10))
Answer:
BC=11
Step-by-step explanation:
we need to find BC
and we know that
AB= x+2
AC=13
BC=2x+11
A, B and C are collinear
that means that
AB+BC=AC
x+2+2x+11=13
3x+13=13
3x=0
x=0
so BC=2(0)+11
BC=11