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The sides of a square field are 12 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co

loris [4]

Area of the square is 144m.
Area of the circle is 113.1m.
Subtract A of circle from A of Square which equals 30.9meters. That is your answer.

If you want I can teach you step by step just comment if you want me to...

8 0

3 years ago

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 8/9 and P(T) = 1/10.

blsea [12.9K]

Answer:

$\textbf{$P(S \cap T) = \frac{89}{90}$ }\\$

Step-by-step explanation:

$\textup{Mutually events are events that cannot occur at the same time.}\\\textup{When you toss a coin you get only $head$ or only $tail$ but never both.}\\ \textup{In mathematical terms $P(A) \cup P(B) = 0$, where $A$ and $B$ are mutually exclusive events. }\\\textup{We know the formula:}\\$$ P(A \cup B) = P(A) + P(B) - P(A \cup B) $$\\\textup{When $A$ and $B$ are mutually exclusive, it will simply be:}\\$$ P(A \cup B) = P(A) + P(B) $$\\\textup{Now given:}\\ $P(S) = 8/9$ , $P(T) = 1/10$\\$

$\implies P(S \cup T) = \frac{89}{10}$

6 0

3 years ago

Can someone help!!! And explain please

vlada-n [284]

Answer:

400(π+2) feet square

Step-by-step explanation:

let x be the diagonal of the cage=40√2 at the same time it is the radius of the circle ( the tiger can go in circle)

but since the cage is part of the circle and not full turn πr²/8

area of the circleπr²+ half area square

(π(40√2)²)/8 +40²/2

3200π/8+1600/2

400π+800

400(π+2) feet square

6 0

3 years ago

Find the surface area of a water tower that is 40 feet tall and has a diameter of 20 feet.

Ganezh [65]

Answer:

The surface area is 3140 feet².

What is Surface Area?

Surface area is the amount of space covering the outside of a three-dimensional shape.

Given that:

Diameter = 20 feet

radius = 20 ÷ 2 = 10 feet

Now, Surface area will be,

=2πr²+ 2πrh

= 2 × 3.14 × (10)² + 2 × 3.14 × 10 × 40

= 6.28 × 100 + 6.28 × 400

= 628 + 25.12 × 100

= 628+ 2512

= 3140 feet²

hence, the surface area is 3140 feet².

Step-by-step explanation:

6 0

2 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$