Answer:
Oxygen and carbon dioxide flow through the blood in the placenta. Most of it goes to the heart and flows through the baby's body. At birth, the baby's lungs are filled with fluid. ... Increased oxygen in the lungs causes a decrease in blood flow resistance to the lungs.
Enveloped viral membranes are generally (C)lipid bilayers with associated virus-specific (C)glycoproteins.
Viruses are intracellular parasites that hijack the cellular machinery for their own replication. Therefore, an essential step in the viral life cycle is the transfer of the viral genome into cells. Enveloped viruses (viruses with a lipid envelope) use a two-step process to release their genetic material into the cell.
It first binds to specific surface receptors on target cell membranes and then fuses with these. Viruses and cell membranes. This last step can occur at the cell surface or after internalization of the virus particle by endocytosis or another pathway (such as micropinocytosis).
Strikingly, the virus-cell-membrane fusion process proceeds along essentially the same intermediate steps as other membrane fusions that occur, for example, in vesicle fusion at neural synapses or cell-cell fusion in yeast mating. Fusogens, special viral proteins, facilitate the fusion of viruses and cell membranes.
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The infant should receive the long-term care in a home environment because it promotes more family interaction and less of a hospital environment.
Answer:
What this statement means is that experimentation is not enough, but that true knowledge comes from the analysis of results in a critical and meticulous way
Explanation:
Scientific knowledge is based on the scientific method and the results of the research, however that information is useless if it is not interpreted.
When the results are analyzed by scientists who support the same theories and have the same opinions, the results are not enriched as much as when exposed to different points of view. The debate tests the hypothesis giving rise to more complete answers.
Answer:
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
Explanation:
Given that:
The allele → R = Red beetles
The allele → B = Blue beetles
Since the gene color shows a codominant allele
The Red Beetle = RR
The blue beetles will be = BB
The heterozygous beetle will be = RB
∴
The punnet square showing the crossing of RB × RR is:
R B
R RR RB
R RR RB
The result shows that we have two red beetles and two heterozygous beetles.
Hence;
The genotypic frequency = 1:1
The phenotypic frequency = 1:1
