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liraira [26]
3 years ago
15

Andrea's fish tank holds 30 gallons of water. Andrea estimates that every inch of a fish's length requires a gallon of water. Sh

e wants to purchase some corydoras that are 2 inches long, angelfish that are 5 inches long, and fancy guppies that are 3 inches long. Write an equation for the situation.
Mathematics
1 answer:
Anton [14]3 years ago
3 0
2x + 5y + 3z = 30 is might be the equation.


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Is 7500000 meters greater than 750 kilometers
monitta
A kilometer is 1000 meters.
1000 time 750 equals 750000
So the answer is yes, 7500000 is greater than 750000
5 0
3 years ago
Can someone please give me the right answer.
MrRa [10]

Answer:

Y=106

X=18

Step-by-step explanation:

Both sides would have 65° because of the Alternet interior angles.

180° minus the 65° gives you 115° when you solve for X and solve for Y Use the 115° as shown in the photo below

8 0
3 years ago
−6−1.5(4b+8)=3(−6−2b)
____ [38]

Answer:

-18 = -18  It is true.

Step-by-step explanation:

-6 -1.5(4b+8) = 3(-6 -2b)

 -6   -6b - 12 = -18 -6b

      -6b -18    = -18 -6b

       +6b                 +6b

            -18   =  -18

              It is true.

4 0
3 years ago
Tan9 - tan27 - tan63 + tan 81 = ?
ludmilkaskok [199]
Tan9−tan27−tan63−tan81
tan9+tan81−tan27−tan63
sin9/cos9+sin81/cos81−sin27/cos27−sin63/cos63
sin90/cos81cos9−sin90/cos63cos27
1/sin9cos9−1/sin27cos27
2/sin18−2/sin54
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8 0
2 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
2 years ago
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