Answer:
And rounded up we have that n=421
Step-by-step explanation:
We know that the sample proportion have the following distribution:
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by 
and 
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that 
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We assume that a prior estimation for p would be 
since we don't have any other info provided. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=421
Answer: 30 m ; (or, write as: "30 meters") .
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Explanation:
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Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
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or, write as: A = ( b₁ + b₂) h / 2 ;
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in which: A = area;
b₁ = length of "base 1" (choose either one of the 2 (two bases);
b₂ = length of "base 2" (use the base that is remaining);
h = height of trapezoid;
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From the information given:
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A = 100 m² ;
h = 5 m
b₁ = 10 m
b₂ = x
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Find "x", which is: "b₂" ;
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A = ( b₁ + b₂) h / 2 ;
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Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
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100 m² = [(10m + x) (5m)] / 2 ; Solve for "x" ;
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(10m + x) (5m) = (2)* (100m²) ;
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(5m) (10m + x) = 200 m² ;
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Note: The distributive property of multiplication:
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a(b+c) = ab + ac ;
a(b−c) = ab <span>− ac ;
</span>____________________________________________
We have: (5m) (10m + x) = 200 m² ;
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So: (5m) (10m + x) = (5m*10m) + (5m * x) ;
= 50m² + (5m)x ;
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→ 50m² + (5m)x = 200m² ;
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Divide the ENTIRE equation by "5m" ;
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→ { 50m² + (5m)x } / 5m = (200m² / 5m) ;
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→ 10m + x = 40m ;
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Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
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→ 10m + x − 10m = 40m − 10m ;
to get:
→ x = 30 m ; which is our answer.
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Answer: 30 m ; (or, write as: "30 meters") .
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4.1.....the 4 in the ones place is 10 times bigger then the 4 in the tenths place and 100 times bigger then the 4 in the hundredths place and 1000 times bigger then the 4 in the thousandths place
2.4..the 4 in the tenths place is 10 timed bigger then the 4 in the hundredths place and 100 times bigger then the 4 in the thousandths place
3.14...the 4 in the hundredths place is 10 times bigger then the 4 in the thousandths place
5.124...this 4 in the thousandths place is the smallest
Answer:
I believe this would be B
Step-by-step explanation:
The way I do improper fractions is called the 'boot'
It is where you take the whole number and the denominator and circle both of them so it kind of looks like a boot and you multiply those together.
So 5 * 8= 40 then you add your numerator to that which gets you 45, and you keep the denominator the same
So you end up with 45/8
Sorry if its a little confusing
Hope this helps :)
The question is essentially asking for the least common multiple of 20 and 25. There are several ways you can find the LCM. One easy way is to divide the product by the GCD (greatest common divisor).
GCD(20, 25) = 5 . . . . . see below for a way to find this, if you don't already know
LCM(20, 25) = 20×25/GCD(20, 25)
... = 500/5 = 100
The buses will be there together again after ...
... B. 100 minutes
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You can also look at the factors of the numbers:
... 20 = 2²×5
... 25 = 5²
The least common multiple must have factors that include all of these*, so must be ...
... 2²×5² = 100
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* you can describe the LCM as the product of the unique factors to their highest powers. 20 has 2 raised to the 2nd power. 25 has 5 raised to the 2nd power, which is a higher power of 5 than is present in the factorization of 20. Hence the LCM must have 2² and 5² as factors.
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You can also look at the factorization of 20 and 25 to see that 5 is the only factor they have in common. That is the GCD, sometimes called the GCF (greatest common factor).
