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patriot [66]
4 years ago
8

How many ways can a person toss a coin 13 times so that the number of tails is between 7 and 9 inclusive

Mathematics
1 answer:
nexus9112 [7]4 years ago
7 0

Answer:

3718 ways

Step-by-step explanation:

How many ways can a person toss a coin 13 times so that the number of tails is between 7 and 9 inclusive

Probability is the likelihood for an event to occur  or not

The formula for a combination is:

n choose r = n! / (r! x (n-r)!)  

n=13

r=7 to 9

We are going to add up the cases for 7 through 9:

^{n } C_{r}

^{13 } C_{7}+^{13 } C_{8}+^{13 } C_{9}

\frac{n!}{r!(n-r)!}

\frac{13!}{7!(13-7)!}+\frac{13!}{8!(13-8)!}+\frac{13!}{9!(13-9)!}

1716+1287+715

3718 ways

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