Answer:
x=1.6 repeating. I hope this helped
It's important that you share the complete question. What is your goal here? Double check to ensure that you have copied the entire problem correctly.
The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
Check the original problem. If it's different from that which you have shared, share the correct version and come back here for further help.
Louis traveled 7,144 miles
The equation of a circle is:
(x-h)2 + (y-k)2 = r2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2
r= 10
The final equation is:
(x-5)2 + (y+4)2 = 102
