550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
1) the slope of a line is m in the equation y=mx+b, in this case m isn’t there because m=1 so the slope is 1
2) the slope of a perpendicular line of this would be the reciprocal which is -1
Are you graphing this? if so, just plug in for x. . . (-2,9)(-1,0)(0,-1)(1,0)(2,21)
7 ears equal five pounds.
Hello,
T=F*x==>x=T/F=96/16=6 (m)
T is the word (travail in french)
F is the force applied
x is the deplacement.
