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katrin2010 [14]
3 years ago
5

Michael has a bus rental agency. He has 18 buses available, of which 8 have air conditioning (A.C.). What is the probability tha

t a randomly selected vehicle will be an A.C bus? 50% 2/3 4/9 30%

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

4 / 9

Step-by-step explanation:

Solution:-

- Michael bus rental agency has a total of n = 18 buses.

- Out all the available buses he has r = 8 buses with AC in them.

- If we were to randomly select a bus from his agency what is the probability that the bus would have an AC:

           P ( Bus with AC ) = Favorable Outcomes / Total outcomes

                                        = Number of bus with AC / Total Buses

                                        = r / n

                                        = 8 / 18

                                        = 4 / 9

ankoles [38]3 years ago
3 0

Answer:

4/9

Step-by-step explanation:

Please refer to the attached image for explanations

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Answer:

A     32.1

Step-by-step explanation:

Given two points (x_{1} ,y_{1} ) and (x_{2} ,y_{2}))

distance between to points = d = \sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2} }

Now B is (-4,5) and A is (2,0)

So AB = \sqrt{(-4-2)^{2} +(5-0)^{2} }  = \sqrt{36 + 25} = \sqrt{61\\} = 7.810...

C is (4,10)

So BC = \sqrt{(-4-4)^{2} +(5-10)^{2} } =\sqrt{64 + 25) } =\sqrt{89} =9.433...

D is (8,7)

So CD = \sqrt{(4-8)^{2} +(10-7)^{2} } =\sqrt{16 + 9} = \sqrt{25} = 5

E is (4,5)

So DE = \sqrt{(8-4)^{2} + (7-5)^{2} }  = \sqrt{16 + 4}  = \sqrt{20}  =  4.472...

and AE = \sqrt{(4-2)^2 + (5-0)^2} =\sqrt{4+25}  = \sqrt{29} = 5.385...

Perimeter = 7.810 + 9.433 + 5 + 4.472 + 5.385 = 32.1

7 0
3 years ago
Use the conditional statement to answer the question.
anygoal [31]
The statement is true, but the inverse is false.
4 0
4 years ago
Ecologists sometimes find rather strange relationships in our environment. For example, do beavers benefit beetles? Researchers
Harman [31]

Answer:

The appropriate conclusion that answers the question stated in step one is:

  • The weak correlation value does not support the idea that beavers benefit beetles.
  • The largest number of beetle larvae was 55 and the largest number of stumps was 5.

Step-by-step explanation:

1) Select the appropriate practical question.

The appropriate practical question is:

"How does the number of beaver-caused stumps influences the number of beetle larvae clusters?"

2) Make a scatter plot.

The scatter plot is attached below.

From the scatter plot it can be seen that there exists a negative relationship between beaver stumps and beetle larvae. That is as the number of stumps increases the number of beetle larvae decreases.

The maximum number of beaver stumps found is 5.

3)

The best numerical summary for this problem are,

Correlation and regression line

The least square regression line for predicting the number of beetle larvae from the number of stumps is:

<em>y</em> = 31.594 - 2.8365 <em>x</em>.

Use the Excel function "=CORREL(array1,array2)" to compute the correlation.

The correlation value is, <em>r</em> = -0.219.

Both the correlation coefficient and regression line explains a negative relationship between the number of beetle larvae and the number of stumps.

Values amid 0 and 0.3 (0 and -0.3) implies a weak positive (negative) linear relationship amid the variables.

Thus, a correlation coefficient, r = -0.219, indicates a weak negative correlation between two variables.

Thus, the appropriate conclusion that answers the question stated in step one is:

  • The weak correlation value does not support the idea that beavers benefit beetles.
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The answer to this is: x = 0, 5/4
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