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Lelu [443]
3 years ago
10

Uhhh please help me. I dont know why i dont understand this problem

Mathematics
1 answer:
Mariana [72]3 years ago
7 0
The answer is A) because the parabola is less than 3 (open circle) and the line is greater than and equal to 3 (closed circle)
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Please help! Find the domain of y = 4 square root 4x + 2
olga55 [171]

Answer:

x ≥ -1/2

Step-by-step explanation:

We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:

To find our domain, we need to set the square root equal to zero:

√(4x + 2) = 0

4x + 2 = 0

4x = -2

x = -1/2

We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2

Alternatively, we can graph the function and analyze domain:

3 0
3 years ago
Implicit diffrention problems I am really stuck on
AysviL [449]

Answer:

\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

x^4 + x^3y = 5xy^2 -y^3

now differentiating in terms of x (\frac{dy}{dx})

4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )

isolating dy/dx to one side

4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )

4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)

\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}

5 0
3 years ago
12 divided by the sum of h and 2
irinina [24]
Putting this into expression form, it would be: 
12 ÷ (h + 2) 
Hope this helps!
6 0
3 years ago
How do convert 50/6 in the lowest fraction
vovikov84 [41]

\bf \cfrac{50}{6}\implies \stackrel{\textit{some quick prime factoring on both}}{\cfrac{2\cdot 5\cdot 5}{2\cdot 3}}\implies \cfrac{2}{2}\cdot \cfrac{5\cdot 5}{3}\implies 1\cdot \cfrac{5\cdot 5}{3}\implies \cfrac{25}{3}

5 0
3 years ago
I will mark brainiest is my answer is correct?
Kruka [31]
Yes you have the correct one good job.
8 0
3 years ago
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