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3 years ago

(8^4 tu^2)(8^7 t^-1)

Mathematics

1 answer:

Ivanshal [37]3 years ago

5 0

Answer:

I could give you an example but I can't give you an answer

Step-by-step explanation:

To Acquire

The Value of 20/4+8/3

Firstly ,we need to find out the LCM of the denominators

Now,

We've to Multiply the numerator with the number which is divisible by the resulting LCM from the respective denominator

just like ,here ,12/4 = 3 so we'll Multiply 3 by the numerator of 4 i.e 20 => 20*3 = 60

We'll apply the same thing with the other one

12/3=4 => 4*8 = 32

Now ,we will add the resulting numerators and will keep it in a fraction with the denominator = LCM of 4&3=12

60+32/12

92/12

46/6

23/3

7 ⅔

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Create and solve a word problem that involves both Revenue and Cost. Your problem should include Break-Even and graphs of both t

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Answer:

HOLA BB COM O ESTAS DIME QUE TE AYUDO BB

Step-by-step explanation:

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3 years ago

A number added to 3 is equal to negative 5, find the number

anzhelika [568]

Answer:

-8

Step-by-step explanation:

An equation at represents this situation is:

-5 = 3 + x

Find x by;

-5 - 3 = -8

So x is -8:

-5 = 3 + -8 (TRUE)

Hope this helps

6 0

3 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

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3 years ago

How many times do you need to divide by ten to get from 5947.7 to 5.9477 ?

mixas84 [53]

Answer would be 4 times

so if u count from behind 7 to where the decimal point is it would be 4

brainliewst and thanks plz

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3 years ago

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The second one is the correct equation. The constant to the right should be the diameter squared, while the numbers inside the parentheses should be the opposite.

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3 years ago

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