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irga5000 [103]
3 years ago
7

which properties do equilateral triangles and isosceles triangles have in common? A: 0 sides of equal length. B: 2 sides of equa

l lengths. C: 3 sides of equal length. D: 3 equal angles. Multiple choice
Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

2 sides of equal length

Step-by-step explanation:

equaraterial triangle has all side equal isoscles trialgle have 2, side triangle

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A surveyor is estimating the distance across a river. The actual distance is . The surveyor's estimate is . Find the absolute er
Nana76 [90]
<h2>Question:</h2>

A surveyor is estimating the distance across a river. The actual distance is 284.5 m. The surveyor's estimate is 300 m. Find the absolute error and the percent error of the surveyor's estimate. If necessary, round your answers to the nearest tenth.

<h2>Answer:</h2>

(i) Absolute error = 15.5m

(ii) Percent error = 5.5%

<h2>Step-by-step explanation:</h2>

<em>Given:</em>

Actual measurement of the distance = 284.5 m

Estimated measurement of the distance by the surveyor = 300 m

(i) The absolute error is the magnitude of the difference between the estimated value measured by the surveyor and the actual value of the distance across the river.

i.e

Absolute error = | estimated value - actual value |

Absolute error = | 300m - 284.5m | = 15.5m

(ii) The percent error (% error) is given by the ratio of the absolute error to the actual value then multiplied by 100%. i.e

% error = \frac{absoluteError}{actualValue} x 100%

% error = \frac{15.5}{284.5} x 100%

% error = 0.05448 x 100%

% error = 5.448%

% error = 5.5%  [to the nearest tenth]

3 0
3 years ago
Which teacher exhibited the most variable year to year performance over this 5 year span?
vlabodo [156]
I do not have the graph that you are referencing from this question to, but I can help you get led to the right answer. If the teacher exhibits the most variable year to year performance over a 5 year span, then the graph must show unstable fluctuating of figures. Those who are least variable would have a steady line going up or down or maybe even just straight. 
3 0
3 years ago
An item originally costs $16.95 and is on sale for 22% off the original price. The sales tax is 6.5%. Find the cost of the item
olga_2 [115]

Answer:

$14.08

Step-by-step explanation:

$16.95 * 22% = $3.729

$16.95 - $3.729 = $13.221

^ to find the sale price of the item

$13.221 * 6.5% = $0.859

$13.221 + $0.859 = $14.08

^ to add on sales tax to the sale price

8 0
4 years ago
Jessica wants to spend less than $80.00 per month on her cell phone. Write and solve an inequality that shows how many text mess
KiRa [710]

Complete Question

Jessica pays a flat rate of $70 for her cell phone and is charged $0.05 for every text she sends. Jessica wants to spend less than $80.00 per month on her cell phone. Write and solve an inequality that shows how many text messages Jessica must limit herself to in order to keep her monthly bill less than $80.00.

Answer:

<em>Inequality: </em>70 + 0.05x < 80

<em>Solution: </em>x < 200

Step-by-step explanation:

Let x represents the minimum number of SMS.

If 1 SMS is charged at $0.05, then x SMS would be charged at $0.05x

Considering that she pays a flat rate of $70.

The inequality to represent the minimum number of SMS she needs to send is:

70 + 0.05x < 80

To solve this inequality, follow the following steps

Collect like terms

0.05x < 80  - 70

0.05x < 10

Divide through by 0.05

0.05x/0.05 < 10/0.05

x < 10/0.05

x < 200

The solution to the inequality that shows how many text messages Jessica must limit herself to in order to keep her monthly bill less than $80.00 is x < 200.

5 0
4 years ago
Which inequivalnet is equivalent to |x-4|&lt;9
nikklg [1K]

Answer:

something like this?

\left \{ {{x-4  

the top one is valid when x-4 >0

the bottom one is valid when x-4<0

Step-by-step explanation:

absolute value  |x-4|

means that in case x-4 is negative, we will use -(x-4)

if it's positive we use x-4

let's find the solution (where the original inequality is true)

negative case:

-(x-4)<9    -x+4 < 9  -x < 5  x>-5

positive case:

x-4 < 9   x < 13

to satisfy both conditions -5 < x < 13

5 0
3 years ago
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