Question

Identify an equation in point-slope form for the line parallel to y=-2/3x+8 that

Answer 1

Answer:

$\large\boxed{y+5=\dfrac{2}{3}(x-4)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

Parallel lines have the same slope.

We have the equation in the slope-intercept form (y = mx + b)

$y=-\dfrac{2}{3}x+8\to m=\dfrac{2}{3}$

Put to the point-slope equation value of the slope and the coordinates of the point (4, -5):

$y-(-5)=\dfrac{2}{3}(x-4)\\\\y+5=\dfrac{2}{3}(x-4)$