Question

A large flagpole stands outside of an office building. Marquis realizes that when he looks up from the ground 60m away from the flagpole, the top of the flagpole and the top of the building line up. If the flagpole is 35m tall and Marquis is 170m from the building, how tall is the building?

Answer 1

Answer:

99.2m

Step-by-step explanation:

PLEASE TAKE A LOOK AT THE IMAGE ATTACHED

Let's solve for triangle CDE and get the angle D

And since we have the opposite and the adjacent of that particular angle,we make use of the tangent in SOH CAH TOA

TAN X = opp/adj

Tan x = 35/60

X = tan inverse of 35/60

X = 30.26°

We are now going to make use of this angle to find the height of the building

Tan 30.26 = opp/adj

Remember that the boy is 170m away from the building which is our adjacent here.

Tan 30.26 = y/170

Y = 170 × tan 30.26

Y = 99.2m

Therefore, the height of the building is 99.2m

Answer 2

Answer:

99.17m

Step-by-step explanation:

In the diagram, Marquis is at Point A and the flag pole is length DE, the building is of length BC.

Triangles ADE and ABC are therefore similar right triangles.

Applying this,

$\frac{|DE|}{|AE|}=\frac{|BC|}{|AC|}$

$\frac{35}{60}=\frac{|BC|}{170}$

|BC|=170*35÷60

|BC|=99.17m