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Orlov [11]
3 years ago
15

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi on 19 gal

of gas, how many of the gallons (to the nearest gallon) were used for city driving?
Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

Answer:

7 gallons were used for city driving.

Step-by-step explanation:

I am going to solve this question by a system of equations.

I am going to say that:

x is the number of gallons driven in the city.

y is the number of gallons driven in the highway.

19 gal of gas

This means that x + y = 19

Carole's car averages 13.2 mi/gal in city driving and 25.3 mi/gal in highway driving. If she drove a total of 396.0 mi.

This means that 13.2x + 25.3y = 396

How many of the gallons (to the nearest gallon) were used for city driving?

This is x

From the first equation, i will have

y = 19 - x

Replacing in the second equation

13.2x + 25.3y = 396

13.2x + 25.3(19 - x) = 396

13.2x - 25.3x = 396 - 480,7

12.1x = 84.7

x = \frac{84.7}{12.1}

x = 7

7 gallons were used for city driving.

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In Exercises 3 and 4, find the values of x and y <br> plz help!!!
jonny [76]

Answer:

x = 20°

y = 30

Step-by-step explanation:

The triangle given on close inspection, it is an equilateral triangle.

Each angle in an equilateral triangle is equal. Likewise, each side is equal.

Thus;

16 + y = 46

y = 46 - 16

y = 30

The triangle that has angle 80°, the other complete angle is 60° because it's an angle of an equilateral triangle.

Thus, the smaller angle there is;

180 - (80 + 60) = 40°

Because sum of angles in a triangle is 180°

Now, x + 40 = 60°

Since that's also an angle of an equilateral triangle.

x = 60 - 40

x = 20°

8 0
3 years ago
Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?
Vladimir79 [104]
Steve is faster than Paul by 2 seconds after 100m
6 0
3 years ago
Nabin is twice as old as Kiran. Two years hence he will be six years older then Kiran. Find there present age
Jobisdone [24]

Answer:kiran is 2 and Nabin is 4

Step-by-step explanation:

4 0
2 years ago
The perimeter of a square and an equilateral triangle add up to 77 cm. Both figures have
ad-work [718]

Length of each side = 11 cm

Solution:

Let a be the side of the square.

Side length of square = Side length of equilateral triangle

Therefore, side length of equilateral triangle = a

Perimeter of the square = Number of sides × side

                                        = 4 × a

Perimeter of the square = 4a

Perimeter of the equilateral triangle = Number of sides × side

                                                            = 3 × a

Perimeter of the equilateral triangle = 3a

Sum of the perimeter of a square and equilateral triangle = 77 cm

⇒ 4a + 3a = 77

⇒ 7a = 77

Divide by 7 on both sides of the equation, we get

⇒ a = 11 cm

Length of each side = 11 cm.

5 0
3 years ago
4/5 divided by 3/10=
erik [133]
Step 1. Apply this rule: a ÷ \frac{b}{c} =a* \frac{c}{b}

\frac{4}{5} * \frac{10}{3}

Step 2. Apply this rule: \frac{a}{b} * \frac{c}{d} = \frac{ac}{bd}

\frac{4*10}{5*3}

Step 3. Simplify 4 × 10 to 40

\frac{40}{5*3}

Step 4. Simplify 5 × 3 to 15

\frac{40}{15}

Step 5. Simplify

\frac{8}{3}

Done!

7 0
3 years ago
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