F(-3) = -12 - 3 = -15
h(2) = -10 + 7 = -3
-15 + (-3)
-18
I believe The answer is B
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
X, y - the numbers
The numbers add to 9 and multiply to -70.
The numbers are
-5 and 14.
Answer:
The y-intercept is 4
Step-by-step explanation:
y=mx+b
m=the slope
b=the y-intercept
Hope this helps .-.
