3 years ago

Multiply (3x2-2x)(2x2+3x-1)

Mathematics

1 answer:

ELEN [110]3 years ago

8 0

Answer:

(3·x^2 - 2·x)·(2·x^2 + 3·x - 1)

= 3·x^2·2·x^2 + 3·x^2·3·x - 3·x^2·1 - 2·x·2·x^2 - 2·x·3·x + 2·x·1

= 6·x^4 + 9·x^3 - 3·x^2 - 4·x^3 - 6·x^2 + 2·x

= 6·x^4 + 5·x^3 - 9·x^2 + 2·x

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For a rectangle of length L and width W, the diagonal is:

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Here we know that the diagonal is 169m.

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This means that:

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