Answer:
<h3>

</h3>
Step-by-step explanation:
Given,
diameter ( d ) = 12 in
height ( h ) = 15 in
<u>finding </u><u>the </u><u>radius </u><u>of </u><u>a </u><u>cylinder</u>
Radius is just half of diameter.
Radius ( r ) = 12 / 2 = 6 in
<u>finding </u><u>the </u><u>volume </u><u>of </u><u>a </u><u>cylinder </u><u>having </u><u>radius </u><u>of </u><u>6</u><u> </u><u>in </u><u>and </u><u>height </u><u>of </u><u>1</u><u>5</u><u> </u><u>in</u>
Volume of a cylinder = <u>
</u>
⇒
⇒
⇒<u>
</u>
Hope I helped!
Best regards!!
First, we know (D is dad, J is Jill) that D+J=50.
Second, in 5 years D will be 3 times as old so
(D+5)= 3*(J+5)
Moving on, if we know D+J=50 then D=(50-J) is true.<span>Taking that relationship and substituting for D in the other equation, it becomes
50 - J + 5 = 3 * (J + 5)
Then, it becomes </span>50 - J + 5 = (3 * J) + (3 * 5)
Then, 55 - J = (3 * J) + 15
Then, 55 - 15 = (3 * J) + J
<span>which becomes 40 = 4*J</span>
Answer:
260 gallons
Step-by-step explanation:
An estimate of 26.5% of the water used each day is for cleaning and a family uses 68.9 gallons of water a day for cleaning,
Percentage of water used for cleaning= 26.5%
Gallons of water used for cleaning= 68.9
Let the number of gallons used everyday be represented by g. This will give:
26.5% of g = 68.9
26.5/100 × g = 68.9
0.265 × g = 68.9
0.265g = 68.9
Divide both side by 0.265
0.265g/0.265 = 68.9/0.265
g= 260
260 gallons of water are used everyday
Answer:
Average Cost per game for 4 games is:
A) $4.75
Step-by-step explanation:
As the question is not complete, lets complete it first.
At the bowling Alley, shoe rentals cost $3 while a games costs $3. The expression that represents the average costs per game 'c' , in dollars, where n is the number of games, is:

To find average cost per game, for 4 games, simpli substitute n=4 into the given equation:

So Average Cost per game for 4 games is:
c = 4.75$
Assuming that the garden is rectangular in shape, the area of a rectangle is given by length x width.
11 is a prime with factors 1 and 11.
Therefore, if the area of a (rectangular) garden is 11 square feet, then the possible dimension of the garden is 1 feet by 11 feet.