The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A)
<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>
<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>
Now we group applying what we see above
<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>
<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>
<span>Now the given expression is: </span>
<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>
<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
1/2 of 8 is 4 so then 1/2 of 4 is 2
so the lawn ornament is 4 ft
Answer:
a) 
b) The lowest point of 
, 
is when x = 
Step-by-step explanation:
a) To simplify the expression 
you must:
Apply Difference of Two Squares Formula: 
Apply the Pythagorean Identity 
From the Pythagorean Identity, we know that 
Therefore,
![324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325](https://tex.z-dn.net/?f=324%5B-%5Ctan%20%5E2%5Cleft%28x%5Cright%29%2B%5Csec%20%5E2%5Cleft%28x%5Cright%29%29%5D%5C%5C324%5B%2B1%5D%5C%5C325)
b) According with the below graph, the lowest point of , is when x =
This can be solve by first solving the proportionality constant
Number electic outlets rewired is directly proportional to
time spent
4 = (1 ½)a
Let be the proportionality constant
A = 8/3
O = (8/3)(7.5)
o = 20 outlets will jamal rewired if he works for 7.5 hrs
