It is defined as a function that is sinusoidal in nature, and it has a domain of all real numbers and lies between the [a, a]where is the amplitude of the function.

As we know the sin function is represented by:

y = Asin(Bx) + C

Here,

A = The amplitude = 3

C = The vertical shift = 1

B - The period in terms of π

B = 2π/amplitude

B = 2π/4

B = π/2

The becomes:

$\rm y = 3sin(\dfrac{\pi }{2}x)+1$

Thus, the equation of the sin function is y = 3sin(πx/2) + 1, and the graph of the function is shown in the picture.

Learn more about the sin function here:

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3 0

2 years ago

A, E, and D are collinear. BCDE is a parallelogram. Find m

zmey [24]

Answer:

Step-by-step explanation:

Penis

3 0

4 years ago

Write in slope-intercept form an equation of the line that passes through the point (r,p) with slope q.

-BARSIC- [3]

Answer:

y=q(x-r)+p

Step-by-step explanation:

y-y1=m(x-x1)

y-p=q(x-r)

y=qx-qr+p

y=q(x-r)+p

8 0

3 years ago

Find the area please

tatuchka [14]

Answer:

Step-by-step explanation:

Recall that the area of a triangle is given by:

$\displaystyle A = \frac{1}{2} bh$

In this case, the base is <em>x</em> and the height is <em>y</em>. Hence:

$\displaystyle A = \frac{1}{2} xy$

We can write the following ratios:

$\displaystyle \sin \alpha = \frac{x}{12} \text{ and } \cos \alpha = \frac{y}{12}$

Solve for <em>x</em> and <em>y</em>:

$\displaystyle x = 12\sin \alpha \text{ and } y = 12\cos \alpha$

Substitute:

$\displaystyle A = \frac{1}{2}\left(12\sin \alpha\right)\left(12\cos \alpha\right)$

And simplify. Hence:

$\displaystyle A = 72\sin \alpha \cos\alpha$

In conclusion, our answer is D.

6 0

3 years ago