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kipiarov [429]
3 years ago
6

Which pair of undefined terms is used to define the term parallel lines?

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0
<span>After a thorough research, there exists the same question that have choices.

</span><span>Point, line
Line, plane
Coplanar, line
Point, coplanar </span><span>

The correct answer is "Coplanar, Line." The pair of undefined terms that is used to define the term parallel line is "Coplanar, Line" because parallel lines are coplanar in itself that do not intersect.
</span><span>

</span>
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What is z equal to ? Please help
MakcuM [25]
The sum of the interior angles of a triangle (half the rhombus in this case) is 180. Because of the properties of a rhombus, z and x will be equal to each other. Therefore, 124 + z + z = 180.
124 + z + z = 180
124 + 2z = 180
2z = 56
z = 28
Thus, z is equal to 28.




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A triangle has an angle that measures 90 degrees what type of triangle could it be​
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8 – 6 ∙ 4 + 10 ÷ 2 =
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Answer:

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Step-by-step explanation:

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. A _____ is a flat surface that has no thickness.
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Answer: plane

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Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
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