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kipiarov [429]
3 years ago
6

Which pair of undefined terms is used to define the term parallel lines?

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0
<span>After a thorough research, there exists the same question that have choices.

</span><span>Point, line
Line, plane
Coplanar, line
Point, coplanar </span><span>

The correct answer is "Coplanar, Line." The pair of undefined terms that is used to define the term parallel line is "Coplanar, Line" because parallel lines are coplanar in itself that do not intersect.
</span><span>

</span>
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Evaluate the function f(x)=x^2+6x+2 at the given values of the independent variable and simplify.
____ [38]

Answer:

a) 18

b)x^2+10x+18

c)x^2 -6x+2

Step-by-step explanation:

This is a case of plugging in the value into f(x).

a) f(-8)= -8^2 + 6(-8) +2

f(-8)= 64 + (-48) +2

f(-8)=64 + (-46)

f(-8)=18

b)  f(x+2)= (x+2)^2+6(x+2)+2

So here I'll take a break to explain what's going on, because x+2 is a binomial meaning two terms and it is being squared I have to multiply the whole thing by itself. Meaning: (x+2) x (x+2), this is also known as foiling!! and for the next part its distributing 6 into x and 2.

    f(x+2)= x^2+4x+4+6x+12+2

I'll reorder it

 f(x+2)= x^2+4x+6x+12+2+4

    f(x+2)= x^2+10x+18

c) f(-x)= -x^2+6(-x) +2

f(-x)= x^2 -6x+2

6 0
2 years ago
What is the area of the triangle?
Alika [10]

Answer:

15 I think

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
You went to Disneyland and spent $50 on your ticket to get in. You also spent 1/3 of your money on food and fun Disney stuff. Yo
Papessa [141]

Answer:

125

Step-by-step explanation:

6 0
3 years ago
One of the tents you look at has a base measuring 3 metres long and 250 centimetres wide what is the area of the tent
ozzi
3 +250= 253 take 253 dived it by 3 ,subtract 4 =80.3
5 0
3 years ago
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