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3 years ago

40 miles x 25 min.=?mph

1 answer:

4 0

$\bf \stackrel{miles}{40}~in~\stackrel{minutes}{25}\implies \cfrac{40~miles}{25~\underline{minutes}}\cdot \cfrac{60~\underline{minutes}}{hr}\implies \cfrac{40\cdot 60~miles}{25~hr}
\\\\\\
\cfrac{2400}{25}\cfrac{miles}{hr}\implies 96\frac{miles}{hr}$

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Gekata [30.6K]

Answer:

Step-by-step explanation:

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3 years ago

Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re

attashe74 [19]

Answer: $\frac{11}{15}$

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

$LCM=5*3=15$

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

$\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}$

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3 years ago

Lincoln's monthly bank statement showed the following deposits and withdrawals:

gayaneshka [121]

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2 years ago

Natalie and John are both saving coins in jars for a rainy day. Natalie currently has 1 1/8 jars of coins, and John has 9/14 of

aivan3 [116]

Answer:

Natalie will have $1\frac{43}{56}$ jars of coins all together after receiving John's coins.

Step-by-step explanation:

Given that:

Coins Natalie have = $1\frac{1}{8}$ jars of coins

Coins John have = $\frac{9}{14}$ jars of coins

When John will give all his coins to Natalie.

Total coins Natalie have = Her coins + John's coins

Total coins Natalie have = $1\frac{1}{8}+\frac{9}{14}$

Total coins = $\frac{9}{8}+\frac{9}{14}$

Total coins = $\frac{63+36}{56}=\frac{99}{56}$

Total coins = $1\frac{43}{56}$

Hence,

Natalie will have $1\frac{43}{56}$ jars of coins all together after receiving John's coins.

5 0

3 years ago

Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria. Latoya served 10 more orders than Milan, Ho

Tems11 [23]

Orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.

<u>Solution:</u>

Given, Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria.

Let orders served by Latoya ne a, orders served by Milan be b and orders served by hong be c.

Then, a + b + c = 154 ⇒ (1)

Latoya served 10 more orders than Milan, ⇒ a = b + 10

Hong served 4 times as many orders as Milan. ⇒ c = 4b

We have to find how many orders did they each serve?

Now, substitute a and c values in (1)

(b + 10) + b + 4b = 154

b + b + 4b = 154 – 10

6b = 144

b = 24

Then, a = 24 + 10 = 34 and c = 4 x 24 = 96.

Hence, orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.

5 0

2 years ago