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harkovskaia [24]

3 years ago

8

During a camping trip, Tony hikes 13 1/2 mi in one day. He hikes 2 1/4 mi each hour. How many hours does it take Tony to complet

e his hike?

2 answers:

garik1379 [7]3 years ago

7 0

It will take 6 hours for Tony to finish his hike.

seraphim [82]3 years ago

6 0

It will take tony 6 hours to complete his hike<span />

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WILL RECIEVE BRANILIEST IF ANSWERED CORRECT

MatroZZZ [7]

Answer:

-27

Step-by-step explanation:

rational number, in arithmetic, a number that can be represented as the quotient p/q of two integers such that q ≠ 0. In addition to all the fractions, the set of rational numbers includes all the integers, each of which can be written as a quotient with the integer as the numerator and 1 as the denominator.

6 0

2 years ago

The formula for the nth square number is S_n = n^2. Use the formula to find the 11th square number.

Klio2033 [76]

Answer:

121.

Step-by-step explanation:

$S_{11} = 11^{2} = 121.$ So, the 11th square number is 121.

4 0

3 years ago

If angle 1 is not congruent to angle 2, which conclusion must be true?

netineya [11]

That they are not congruent

3 0

3 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago

Iii) Find the values of x<br> when y = 1

NeX [460]

If x = 3 and y = - 1 , find the values of the following using in identity: (9y^2 - 4x^2)(81y^4 + 36x^2y^2 + 16x^4)
Answer · 1 vote
Formula, a^3 - b^3 = (a - b)(a^2 + ab + b^2) a^3 + b^3

4 0

3 years ago