In the figure,ABC is congruent to ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', the ratio of the area of A'B'C'D' to the area of ABCD is 1/2. Since the dilation is by a factor of 2, so the area of the A'B'C'D' should be smaller than the area of ABCD.
For a;
For b;
If my calculations are incorrect, then sorry ;/
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Answer:
the standard form of y=5x+0.5 is B=-5x+y=0.5