To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
With each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5.
<h3>What is slope-intercept form?</h3>
The slope-intercept form is just a means of stating a line's equation so that both the slope (steepness) as well as y-intercept (where another line crosses this same vertical y-axis) are obvious. This expression is frequently referred to as y = mx + b.
<h3>According to the given information:</h3>
To begin, are using the slope formula to figure out the average slope between two points here.
Let:
x1 = 4
y1 = -1
x2 = -2
y2 = -1
m = (y2-y1)/(x2-x1)
= (-1 - (-1))/ (4-(-1))
= 0/5
= 0
So the slope is 0.
We must now calculate the y-intercept. This will be accomplished by converting a single of the points and also the slope together into a point-slope linear equation. y2-y1 = m(x2-x1).
Let’s plug in the point (5,0).
So we get y-(-0) = (0/5)(x-(-5)) ⇒ y+0
= (0/5)x + 0 ⇒ y
So,
Y = 0
X = 5
with each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5
To know more about slope-intercept visit:
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9x + 4= 5x + 20 (alternate interior angles)
9x-5x =20-4
4x = 16
x= 16/4
x= 4
Answer:
C
Step-by-step explanation:
In a parallelogram, consecutive angles are supplementary, sum to 180° , so
3y + 108 = 180 ( subtract 108 from both sides )
3y = 72 ( divide both sides by 3 )
y = 24 → C
