Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
2(-1)
x = <u>-8 +/- √(64 - 20)</u>
-2
x = <u>-8 +/- √(44)
</u> -2<u>
</u>x = <u>-8 +/- 2√(11)
</u> -2
x = <u>-8 + 2√(11)</u> x = <u>-8 - 2√(11)
</u> -2 -2<u>
</u>x = 4 - √(11) x = -8 + √(11)
Answer:
see below
Step-by-step explanation:
16x^2 − 8x + 1
(4x)^2 -8x +1
Factor
This is a perfect square trinomial
a^2 -2ab +b^2 = (a-b)(a-b)
(4x)^2 -8x +1 = (4x-1) (4x-1)
The area of a square is given by
A = s^2
(4x-1) ^2 = s^2
4x-1 = s
The side length is 4x-1
(81x^2 − 4y^2)
(9x)^2 - (2y)^2
This is the difference of squares
a^2 - b^2 = (a-b) (a+b)
(9x-2) (9x+2)
The area of a rectangle is
A = l*w
(81x^2 − 4y^2) = (9x-2) (9x+2)
The dimensions are (9x-2) (9x+2)
Answer:
5
Step-by-step explanation:
1,2,5
Answer:
I believe it to be C
Step-by-step explanation:
