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3 years ago

We know its tens place and hundred thousandths place but how are they related?

Mathematics

2 answers:

AleksAgata [21]3 years ago

8 0

Well each is still a 3 but with 0s

OLga [1]3 years ago

7 0

Each is 3 but with 0

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Marcos drops a bouncy ball from a hieght of 40 feet. The ball loses 10% of its maximum height on each bounce. How high will it b

iren [92.7K]

I think after the 9th bounce it will lose 90% of its max height

times 40 by 0.9 which will give you 36
then take 36 away from 40 leaving you with 4.

answer = 4ft

4 0

3 years ago

Which of the following waves allows us to see colors?

topjm [15]

Gamma rays are radiation.
Radio waves are sound.
Visible light is color.
X-Rays allow us to see bones.

//Your answer is Visible Light.\\

~Mstar180\/\

3 0

3 years ago

Read 2 more answers

Slope for y=5,520.619x - 1,091.393

Bad White [126]

Answer:

m = 5,520.619

Step-by-step explanation:

The given equation is :

y=5,520.619x-1,091.393 ....(1)

The general form of equation is given by :

y = mx +c ...(2)

Where

m is slope of line

c is y-intercept

Comparing equation (1) and (2), we get :

Slope, m = 5,520.619

Hence, the slope of the given line is 5,520.619.

3 0

3 years ago

Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

3 years ago

65% of what number is 39?

aleksklad [387]

You have to turn 65 into a decimal. That would be .65
They do 39/.65
You should get 60 as your final answer.

6 0

3 years ago

Read 2 more answers