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VLD [36.1K]
3 years ago
8

How do you solve 3|x-2|-10=11

Mathematics
1 answer:
Westkost [7]3 years ago
3 0
     3|x - 2| - 10 = 11
    3(x - 2) - 10 = 11      U       3(x - 2) + 10 = -11
3(x) - 3(2) - 10 = 11    U    3(x) - 3(2) + 10 = -11
       3x - 6 - 10 = 11       U        3x - 6 + 10 = -11
            3x - 16 = 11           U           3x + 4 = -11
   3x - 16 + 16 = 11 + 16            3x + 4 - 4 = -11 - 4
                  3x = 27               U              3x = -15
                   3      3                                  3       3
                   x = 9                 U                 x = -5
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enot [183]

Option B

<u>ANSWER:  </u>

The factors of  $x^{3}+2 x^{2}+x$ is $x(x+1)^{2}$

<u>SOLUTION: </u>

Given, cubic expression is  $x^{3}+2 x^{2}+x$

Now, we have to find the factors of above equation.

To factorize the given equation, follow the below steps:

$\mathrm{x}^{3}+2 \mathrm{x}^{2}+\mathrm{x}$

Since x is common in every term of expression, we can take it as common

$x\left(x^{2}+2 x+1\right)$

“2x” can be rewritten as “x + x”, the above equation becomes,

$x\left(x^{2}+x+x+1\right)$

Taking the common terms out of bracket. we get

x(x (x + 1) + 1 (x + 1))  

Taking (x + 1) as common., we get

x ((x + 1)(x + 1))  

$x(x+1)^{2}$

Hence, the second option b is correct.

7 0
4 years ago
Write an equation for the trend line in slope-intercept form. <br><br> Please help me !
anastassius [24]

Answer:

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The sum of two consecutive even numbers is 54 Find the numbers?
pogonyaev

Answer:

26 and 28

Step-by-step explanation:

1st integer = x

2nd integer = x + 2

 

x + x + 2 = 54

2x + 2 = 54

2x = 52

 x = 26

 

The 1st integer is 26.

The 2nd integer is 28.

 

 

Let's add these numbers.

 

26 + 28 = 54

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Answer:

3

Step-by-step explanation:

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3 years ago
8. The straight line depreciation equation for a car is
kifflom [539]

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We have given that the

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y = -10720 + 26,800.

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Suppose that M represents the length of time in months when

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An algebraic expression to represent the value of this car after M months.

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