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VLD [36.1K]
3 years ago
8

How do you solve 3|x-2|-10=11

Mathematics
1 answer:
Westkost [7]3 years ago
3 0
     3|x - 2| - 10 = 11
    3(x - 2) - 10 = 11      U       3(x - 2) + 10 = -11
3(x) - 3(2) - 10 = 11    U    3(x) - 3(2) + 10 = -11
       3x - 6 - 10 = 11       U        3x - 6 + 10 = -11
            3x - 16 = 11           U           3x + 4 = -11
   3x - 16 + 16 = 11 + 16            3x + 4 - 4 = -11 - 4
                  3x = 27               U              3x = -15
                   3      3                                  3       3
                   x = 9                 U                 x = -5
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Answer:

Step-by-step explanation:

12x+2y=36

2y=36-12x

5x+36-12x=22

7x=14

x=2

2y=36-12(2)

2y=12

y=6

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In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=-6x%5E4-3x%5E2y%5E2%20%2B%205y%5E4" id="TexFormula1" title="-6x^4-3x^2y^2 + 5y^4" alt="-6x^4-3
Mashutka [201]

Answer:

the answer to the question is 8x⁴- 5x²y² - 6y⁴  

Step-by-step explanation:

the normal way of using BODMAS is apply to all polynomial equations.

subtracting  -6x⁴- 3x²y² + 5y⁴ from 2x⁴ - 8x²y² - y⁴.

polynomial of the same degree is very easy to calculate. this equation is having the same degree of polynomial all through, therefore:

  Applying Bracket to the equation

   2x⁴ - 8x²y² - y⁴- ( -6x⁴- 3x²y² + 5y⁴)

  Open the bracket

   2x⁴ - 8x²y² - y⁴ +6x⁴+3x²y² - 5y⁴

  collects the likes terms

   2x⁴ +6x⁴- 8x²y² +3x²y² - 5y⁴  - y⁴

  The final answer is =

   8x⁴- 5x²y² - 6y⁴  

6 0
4 years ago
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