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Andreyy89
2 years ago
6

Solve the following problems a.2ft5in+9inches=, b. 4yd8in+6yd6in=​

Mathematics
1 answer:
Luda [366]2 years ago
3 0

Answer:

a. 38

b. 374

Step-by-step explanation:

a. 2 ft = 24 in + 5 in+ 9 in = 38 in

b. 4 yd = 144 + 6 yd = 216

144 + 216 + 8 + 6 = 374

Hope this helps!

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At what points is the function y= cosx/4x continuous<br><br>​
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5 0
2 years ago
The question says “The image shows the front of Bob’s barn.Bob plans on painting the front of his barn,not including the doors o
AleksandrR [38]

Bob need to paint 205 square feet.

Solution:

Length of the door = 7 ft

Breadth of the door = 5 ft

Area of the door = length × breadth

                            = 7 × 5

                            = 35

Area of the door = 35 ft²

The given image is a trapezoid.

Top base = 12 ft

Bottom base = 20 ft

Area of the trapezoid = \frac{1}{2} \times\text{sum of the parallel sides}\times\text{height}

                                    $=\frac{1}{2}\times(12+20)}\times15

                                    $=\frac{1}{2}\times 32\times15

                                    = 240

Area of the trapezoid =  240 ft²

Surface area to paint = Area of the trapezoid – Area of the door

                                    = 240 ft² – 35 ft²

                                    = 205 ft²

Hence Bob need to paint 205 square feet.

6 0
3 years ago
100 POINTS!!!!! AND BRAINLIEST!!!!!!
Aleksandr-060686 [28]

Answer:

x = 6/3y+1

Step-by-step explanation:

x+3xy=6

Step 1: Factor out variable x.

x(3y+1)=6

Step 2: Divide both sides by 3y+1.

x(3y+1) / 3y+1

so x = 6/3y+1

6 0
1 year ago
Read 2 more answers
4, 8, 12, 16, 20 24, 36, 40 44 48 52 56 60 64 68 72 76 80 84 88 92 96 100... Those are the multiples of 4. Now find out which ar
Lilit [14]

Answer:

Ok the answer of 6 are  12, 18, 24, 30, 36, 42, and 48. The multiples of 9 are 18,27,36,45,54,63,72,81,90,99,108,117,126,135,144,153,162,171,180,189,198,. Hope it helps!

7 0
3 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
2 years ago
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