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mixas84 [53]
4 years ago
5

Factor 1/7 out of 1/7x+1/17

Mathematics
1 answer:
nydimaria [60]4 years ago
6 0

Answer:

Step-by-step explanation:

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–735 = 15(m + 929) m = _______
Rina8888 [55]

Answer:

-978

Step-by-step explanation:

1.) Use Distributive property (by multiplying 15 by the values in parentheses): -735=15m + 13935

2.) Subtract 13,935 on both sides, to move that value to the left side, to further  isolate the variable m.

-735-13935=15m + 13935 - 13935

3.)-Simplify/Combine Like Terms

-14,670=15m

4.) Divide both sides by 15 to isolate and solve for m

-14,670/15=15m/15

5.) Simplify

-978=m    

6.) Rearrange so m is on left side and value is on right side

m=-978

5 0
3 years ago
Find the value of each variable so that PQRS is a parallelogram. Explain what allows you to do this.
Nataly [62]

Answer:

x = 5

y = 16

Step-by-step explanation:

Given

See attachment for parallelogram

Required

Find variables x and y

Solving for x, we have:

5x = 25 ---- Opposite sides of a parallelogram

\frac{5x}{5} = \frac{25}{5} ------ Divide both sides by 5

x = 5

Solving for y, we have:

3y - 1 = 47 ---- Opposite sides of a parallelogram

3y = 1 + 47 ------ Collect like terms

3y = 48

\frac{3y}{3} = \frac{48}{3} ---- Divide both sides by 3

y = 16

4 0
3 years ago
Nick went canoeing on the river he traveled 1 mile in 17 minutes.at this rate,how far will he travel in an hour and 25 minutes​
dem82 [27]

9514 1404 393

Answer:

  5 miles

Step-by-step explanation:

An hour and 25 minutes is 85 minutes. Using the given information we can find the distance d with the proportion ...

  \dfrac{\text{distance}}{\text{time}}=\dfrac{d}{85\text{ min}}=\dfrac{1\text{ mi}}{17\text{ min}}\\\\d=\dfrac{85\text{ min}}{17\text{ min}}(1\text{ mi)}\qquad\text{multiply by $85$ min}\\\\d=5(1\text{ mi})\qquad\text{simplify}\\\\d=\boxed{5\text{ mi}}

In 1 hour and 25 minutes, Nick will travel 5 miles.

6 0
3 years ago
Whats the unit rate for $2.50 for 5 ounces
kumpel [21]

For this case what we should do is find the cost per ounce.

For this, we can use the following rule of three:

5 ounces ----------------------> 2.50 $

1 oz ------------------------> x

From here, we clear the value of x.

We have then:

x = (\frac{1}{5}) * (2.50)\\x = 0.5

Answer:

The unit cost per ounce is given by:

x = 0.5 $ / ounce

4 0
3 years ago
Read 2 more answers
When Han makes chocolate milk, he mixes 2 cups of milk with 3 tablespoons of chocolate syrup. Here is a table that shows how to
Korvikt [17]

Answer:

Part a) The table shows a proportional relationship between tablespoons of chocolate syrup and cups of milk

Part b) The scale factor is 1.5

Part c) The constant of proportionally for this relationship is 1.5

Part d) The units for the constant of proportionality are tablespoons of chocolate syrup per cups of milk

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line

Let

x ----> the quantity of cups of milk

y ----> the quantity of tablespoons of chocolate syrup

k ---> the constant of proportionality

For y=3, x=2 -----> k=\frac{y}{x}=\frac{3}{2}=1.5

For y=12, x=8 -----> k=\frac{y}{x}=\frac{12}{8}=1.5

For y=3/2, x=1 -----> k=\frac{y}{x}=\frac{(3/2)}{1}=1.5

For y=15, x=10 -----> k=\frac{y}{x}=\frac{15}{10}=1.5

therefore

The table shows a proportional relationship between tablespoons of chocolate syrup and cups of milk

The linear equation is

y=1.5x

That means----> The the quantity of tablespoons of chocolate syrup is 1.5 times the quantity of cups of milk

The scale factor is equal to the ratio between tablespoons of chocolate syrup and cups of milk. Is equal to the constant of proportionality k

The scale factor is 1.5

The constant of proportionality is 1.5

The units for the constant of proportionality are tablespoons of chocolate syrup per cups of milk

\frac{tablespoons\ of\ chocolate\ syrup}{cups\ of\ milk}

3 0
3 years ago
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