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bija089 [108]
3 years ago
13

Explain how to write 5/3 as a product of a whole number and unit fraction

Mathematics
2 answers:
geniusboy [140]3 years ago
5 0
The question is asking for the product, that means multiplication.Multiply a whole number and a fraction to get 5/3. Then you multiply across the numerator and across the denominator. So multiply 2 numbers to get 5 a decimal 2 numbers to get 3. So

5 × 1 = 5 and 3 × 1 = 3

Multiply.

5 × 1/3 = 5/1
5/1 × 1/3 = 5/3


Thank you for your question, please choose me as Brainliest Answer so that I can help you with all your questions!

777dan777 [17]3 years ago
3 0
Since they want a product, that means multiplication. We want to multiply a whole number and a fraction to get 5/3. When we multiply fractions, you multiply across the numerator and across the denominator. So in this case we want to multiply 2 numbers to get 5 a decimal 2 numbers to get 3. Each of these numbers only have 2 factors so
5 × 1 = 5 and
3 × 1 = 3

So we are going to multiply

5 × 1/3 =
5/1 × 1/3 = 5/3
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Elanso [62]
For red is it is 9/41 and or blue it is 10/41 so together 19/41 so the answer  is b: 19/41

7 0
4 years ago
What are 10 different words for addition , subtraction, Divison
Elenna [48]
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Subtraction: difference, minus, take away, fewer than, less than, decreased by are not, change  

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4 0
3 years ago
Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to
katen-ka-za [31]

Answer:

- 0.7

Step-by-step explanation:

We are given the general quadratic formula, as " x = -b \frac{+}{-}  \sqrt{(b^2-4ac)} / 2a. " This can be represented by two separate formula's, which will come in handy when determining the positive and negative roots of the equation ( and here we need the negative root ):

1 ) x = - b+ ( \sqrt{b^2-4ac} ) / 2a,

2 ) x = - b- ( \sqrt{b^2-4ac} ) / 2a

We know that a = 1, b = - 5, and c = - 4 from the equation " 0 = x^2 - 5x - 4 " ( which can be rewritten in the form 0 = ax^2 + bx + c ). Therefore, simply plug in these values into the quadratic formula to receive two solutions:

x = 5 + ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 + ( \sqrt{25 + 16} ) / 2,\\x = 5 + \sqrt{41} / 2,\\x = ( About ) 5.7- This is our positive solution

__________

x = 5 - ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 - ( \sqrt{25 + 16} ) / 2,\\x = 5 - \sqrt{41} / 2,\\x = ( About ) - 0.7- And this is our negative solution

You can see that - 0.7 is the negative real number solution to Joline's quadratic equation!

4 0
3 years ago
Thanks this answer really helped I got %100 on my test
Rzqust [24]
I don’t understand if this is a math problem or a statement.
3 0
3 years ago
Read 2 more answers
What is the value of x of MNL??
Lynna [10]

Answer:

use the theorem of pythagoras

LM=MN²+LN²

9²=X²+6²

81=X²+36

-x²=36-81

ײ=36+81

ײ=117

x=10

4 0
3 years ago
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